10p^2-75p+65=0

Solution for 10p^2-75p+65=0 equation:

10p^2-75p+65=0

a = 10; b = -75; c = +65;
Δ = b2-4ac
Δ = -752-4·10·65
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-55}{2*10}=\frac{20}{20}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+55}{2*10}=\frac{130}{20}
=6+1/2
$